这篇文章主要介绍“怎么求数据库嵌套表平均值”,在日常操作中,相信很多人在怎么求数据库嵌套表平均值问题上存在疑惑,小编查阅了各式资料,整理出简单好用的操作方法,希望对大家解答”怎么求数据库嵌套表平均值”的疑惑有所帮助!接下来,请跟着小编一起来学习吧!

我创建了一个SCHEMA级别的NUMBER型嵌套表:

CREATEORREPLACETYPEplch_numbers_tISTABLEOFNUMBER/

哪些选项实现了一个名字为plch_avg的函数,能够计算一个上述嵌套表中所有元素的平均值,从而使得下列代码块执行之后会显示"3.5"?

DECLAREl_numbersplch_numbers_t:=plch_numbers_t(1,2,3,4,5,6);BEGINDBMS_OUTPUT.put_line(plch_avg(l_numbers));END;/

(A)

CREATEORREPLACEFUNCTIONplch_avg(numbers_inINplch_numbers_t)RETURNNUMBERISl_indexPLS_INTEGER:=numbers_in.FIRST;l_sumNUMBER:=0;BEGINWHILEl_indexISNOTNULLLOOPl_sum:=l_sum+numbers_in(l_index);l_index:=numbers_in.NEXT(l_index);ENDLOOP;RETURNl_sum/numbers_in.COUNT;END;/

(B)

CREATEORREPLACEFUNCTIONplch_avg(numbers_inINplch_numbers_t)RETURNNUMBERISl_averageNUMBER;BEGINSELECTAVG(COLUMN_VALUE)INTOl_averageFROMTABLE(numbers_in);RETURNl_average;END;/

(C)

CREATEORREPLACEFUNCTIONplch_avg(numbers_inINplch_numbers_t)RETURNNUMBERISBEGINRETURNAVG(numbers_in);END;/

(D)

CREATEORREPLACEFUNCTIONplch_avg(numbers_inINplch_numbers_t)RETURNNUMBERISl_indexPLS_INTEGER:=numbers_in.FIRST;l_averageNUMBER:=0;BEGINWHILEl_indexISNOTNULLLOOPl_average:=l_average+numbers_in(l_index)/numbers_in.count;l_index:=numbers_in.NEXT(l_index);ENDLOOP;RETURNl_average;END;/

(E)

CREATEORREPLACEFUNCTIONplch_avg(numbers_inINplch_numbers_t)RETURNNUMBERISl_averageNUMBER;BEGINSELECTAVG(numbers_in(ROWNUM))INTOl_averageFROMnumbers_in;RETURNl_average;END;/

实测答案ABC

C报错 PLS-00204: 函数或伪列 'AVG' 只能在 SQL 语句中使用

E报错 PL/SQL: ORA-00942: 表或视图不存在

答案ABD, B是最佳答案,注意D在某些情况下可能出现误差。

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