Oracle arraysize的研究是怎样的
Oracle arraysize的研究是怎样的，相信很多没有经验的人对此束手无策，为此本文总结了问题出现的原因和解决方法，通过这篇文章希望你能解决这个问题。
SYS@proc> desc aaa;
Name Null? Type
----------------------------------------- -------- ----------------------------
ID1 NUMBER(38)
ID2 NUMBER(38)
ID3 NUMBER(38)
ID4 NUMBER(38)
SYS@proc> select * from aaa;
ID1 ID2 ID3 ID4
---------- ---------- ---------- ----------
1 1 1 1
1 1 1 0
SYS@proc> select * from aaa1;
ID1 ID2 ID3 ID4
---------- ---------- ---------- ----------
1 1 1 0
1 1 1 1
SYS@proc> select * from aaa where id1/id2=1 and id3/id4=1;
ERROR:
ORA-01476: divisor is equal to zero
no rows selected
SYS@proc> set arraysize 1
SYS@proc> /
ID1 ID2 ID3 ID4
---------- ---------- ---------- ----------
1 1 1 1
ERROR:
ORA-01476: divisor is equal to zero
SYS@proc> select * from aaa1 where id1/id2=1 and id3/id4=1;
select * from aaa1 where id1/id2=1 and id3/id4=1
*
ERROR at line 1:
ORA-01476: divisor is equal to zero
SYS@proc> drop table aaa2 purge;
Table dropped.
SYS@proc> create table aaa2 (id1 int,id2 int,id3 int,id4 int,flag int);
Table created.
SYS@proc> insert into aaa2 values(1,1,1,1,1);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,2);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,3);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,4);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,5);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,6);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,7);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,8);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,9);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,1,10);
1 row created.
SYS@proc> insert into aaa2 values(1,1,1,0,0);
1 row created.
SYS@proc> commit;
Commit complete.
SYS@proc> analyze table aaa2 compute statistics;
Table analyzed.
SYS@proc> set arraysize 1
SYS@proc> select * from aaa2 where id1/id2=1 and id3/id4=1;
ID1 ID2 ID3 ID4 FLAG
---------- ---------- ---------- ---------- ----------
1 1 1 1 1
1 1 1 1 2
1 1 1 1 3
1 1 1 1 4
1 1 1 1 5
1 1 1 1 6
1 1 1 1 7
1 1 1 1 8
1 1 1 1 9
ERROR:
ORA-01476: divisor is equal to zero
9 rows selected.
--从大量结果上看，arraysize为1或者2是一样的。这里为9预见。
SYS@proc> select * from aaa2;
ID1 ID2 ID3ID4 FLAG
---------- ---------- ---------- ---------- ----------
1 1 1 1 1
1 1 1 1 2
1 1 1 1 3
1 1 1 1 4
1 1 1 1 5
1 1 1 1 6
1 1 1 1 7
1 1 1 1 8
1 1 1 1 9
1 1 1 1 10
1 1 1 0 0
11 rows selected.
SYS@proc>
SYS@proc> set arraysize 2
SYS@proc> select * from aaa2 where id1/id2=1 and id3/id4=1;
ID1 ID2 ID3ID4 FLAG
---------- ---------- ---------- ---------- ----------
1 1 1 1 1
1 1 1 1 2
1 1 1 1 3
1 1 1 1 4
1 1 1 1 5
1 1 1 1 6
1 1 1 1 7
1 1 1 1 8
ERROR:
ORA-01476: divisor is equal to zero
8 rows selected.
语句对应的10046，可以看出是返回了9行，但是从上边看是8行，很奇怪。
PARSING IN CURSOR #140496887317072 len=48 dep=0 uid=0 oct=3 lid=0 tim=1514130832420098 hv=3007681721 ad='812bd000' sqlid='7cfwyuytnb55t'
select * from aaa2 where id1/id2=1 and id3/id4=1
END OF STMT
PARSE #140496887317072:c=0,e=1221,p=0,cr=0,cu=0,mis=1,r=0,dep=0,og=1,plh=2576342259,tim=1514130832420093
EXEC #140496887317072:c=0,e=24,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=2576342259,tim=1514130832420198
WAIT #140496887317072: nam='SQL*Net message to client' ela= 5 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832420238
FETCH #140496887317072:c=0,e=64,p=0,cr=2,cu=0,mis=0,r=1,dep=0,og=1,plh=2576342259,tim=1514130832420331
WAIT #140496887317072: nam='SQL*Net message from client' ela= 476 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832420842
WAIT #140496887317072: nam='SQL*Net message to client' ela= 3 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832420907
FETCH #140496887317072:c=0,e=36,p=0,cr=1,cu=0,mis=0,r=2,dep=0,og=1,plh=2576342259,tim=1514130832420924
WAIT #140496887317072: nam='SQL*Net message from client' ela= 146 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421092
WAIT #140496887317072: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421137
FETCH #140496887317072:c=0,e=28,p=0,cr=1,cu=0,mis=0,r=2,dep=0,og=1,plh=2576342259,tim=1514130832421151
WAIT #140496887317072: nam='SQL*Net message from client' ela= 66 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421237
WAIT #140496887317072: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421277
FETCH #140496887317072:c=0,e=26,p=0,cr=1,cu=0,mis=0,r=2,dep=0,og=1,plh=2576342259,tim=1514130832421290
WAIT #140496887317072: nam='SQL*Net message from client' ela= 60 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421369
WAIT #140496887317072: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421407
FETCH #140496887317072:c=0,e=25,p=0,cr=1,cu=0,mis=0,r=2,dep=0,og=1,plh=2576342259,tim=1514130832421420
WAIT #140496887317072: nam='SQL*Net message from client' ela= 410 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421848
WAIT #140496887317072: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832421907
FETCH #140496887317072:c=0,e=63,p=0,cr=1,cu=0,mis=0,r=1,dep=0,og=1,plh=2576342259,tim=1514130832421956
STAT #140496887317072 id=1 cnt=10 pid=0 pos=1 obj=88977 op='TABLE ACCESS FULL AAA2 (cr=7 pr=0 pw=0 time=94 us cost=2 size=10 card=1)'
WAIT #140496887317072: nam='SQL*Net break/reset to client' ela= 28 driver id=1650815232 break?=1 p3=0 obj#=-1 tim=1514130832422110
WAIT #140496887317072: nam='SQL*Net break/reset to client' ela= 120 driver id=1650815232 break?=0 p3=0 obj#=-1 tim=1514130832422252
WAIT #140496887317072: nam='SQL*Net message from client' ela= 595 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1514130832422889
CLOSE #140496887317072:c=0,e=14,dep=0,type=0,tim=1514130832422981
=====================
所以其实arraysize是1还是2，还是存在区别的。不过从10046上看却是没多大区别，从全表扫描或者其他能够正常返回结果的情况下，值为1和2是完全一样的。
但是实际上无论arraysize的值是多少，默认第一行单独会直接发送反馈给用户的，所以应该是不用设置的。
后边研究的逻辑读也有点问题，在12C里边差别更大。
看完上述内容，你们掌握Oracle arraysize的研究是怎样的的方法了吗？如果还想学到更多技能或想了解更多相关内容，欢迎关注亿速云行业资讯频道，感谢各位的阅读！
声明：本站所有文章资源内容，如无特殊说明或标注，均为采集网络资源。如若本站内容侵犯了原著者的合法权益，可联系本站删除。
