#方法1：if语句，练习逻辑能力

num1 = int(input('请输入第一个数：'))

num2 = int(input('请输入第二个数：'))

num3 = int(input('请输入第三个数：'))

if num1 >= num2:

if num1 >= num3:

if num2 >= num3:

print(num3,num2,num1)

else:

print(num2,num3,num1)

else:

print(num2,num1,num3)

else:

if num1 >= num3:

print(num3,num1,num2)

elif num2 >= num3:

print(num1,num3,num2)

else:

print(num1,num2,num3)

#方法2：max min函数排序

num1 = int(input('请输入第一个数：'))

num2 = int(input('请输入第二个数：'))

num3 = int(input('请输入第三个数：'))

nums = []

nums.append(num1)

nums.append(num2)

nums.append(num3)

while True:

cur =min(nums)

print(cur)

nums.remove(cur)

if len(nums) == 1:

print(nums[0])

break

#方法3：sort函数排序

num1 = int(input('请输入第一个数：'))

num2 = int(input('请输入第二个数：'))

num3 = int(input('请输入第三个数：'))

nums =[num1,num2,num3]

nums.sort()

print(nums)

#方法4冒泡法排序

nums = [4,3,5,1]

for i in range(len(nums)-1):

for j in range(len(nums)-i-1):

if nums[j] > nums[j+1]:

nums[j],nums[j+1] = nums[j+1],nums[j]

print(nums)

#方法5：冒泡法排序改进

count_swap = 0

count = 0

nums = [2,3,5,6]

for i in range(len(nums)-1):

flag = False

for j in range(len(nums)-i-1):

count +=1

if nums[j] > nums[j+1]:

nums[j],nums[j+1] = nums[j+1],nums[j]

flag = True

count_swap +=1

if not flag:

break

print(nums,count_swap,count)