矩阵转置，A[i][j] 变成A[j][i] 比较简单，直接上代码了。

func transpose(A [][]int) [][]int { B := make([][]int, len(A[0])) for i := 0; i < len(A[0]); i++ { B[i] = make([]int, len(A)) for j := 0; j < len(A); j++ { B[i][j] = A[j][i] } } return B}