django2.2连oracle11g版本冲突怎么办

2025-01-13 技术教程

小编给大家分享一下django2.2连oracle11g版本冲突怎么办，希望大家阅读完这篇文章后大所收获，下面让我们一起去探讨方法吧！

上次用django2.2和oracle11g，在migrate的时候发生了版本冲突，最终将Oracle升级到了12c才解决问题

那么到底能不能用别的方法来解决这个冲突呢？想了个解决思路，实践一下：

用django2.2连Oracle12c环境下做migrate，创建基础表

将基础表导出，再导入到Oracle11g数据库中

用django2.2连Oracle11g

实施步骤

1、用django2.2连Oracle12c环境下做migrate，创建基础表

在前文中已经完成，连接到数据库，可以看到有10张基础表

看一张表，比如AUTH_GROUP表，发现有个ID字段是用了12c特有的generated语法，除了DJANGO_SESSION外，其他每张表都有一个自增序列的id字段作为主键。

-- Create tablecreate table AUTH_GROUP( id NUMBER(11) generated by default on null as identity, name NVARCHAR2(150))tablespace DJANGO;-- Create/Recreate primary, unique and foreign key constraints alter table AUTH_GROUP add primary key (ID) using index tablespace DJANGO;alter table AUTH_GROUP add unique (NAME) using index tablespace DJANGO;

2. 将基础表导出，再导入到Oracle11g数据库中

导出django用户数据库，注意使用11g版本

接着导入到11g数据库中，非常顺利

再看AUTH_GROUP表，发现表结构是一样的，但是id上面自增序列的默认值没有了。

-- Create tablecreate table AUTH_GROUP( id NUMBER(11) not null, name NVARCHAR2(150))tablespace DJANGO;-- Create/Recreate primary, unique and foreign key constraints alter table AUTH_GROUP add primary key (ID) using index tablespace DJANGO;alter table AUTH_GROUP add unique (NAME) using index tablespace DJANGO;

3、用django2.2连Oracle11g

修改settings文件，连Oracle11g，然后启动django服务，果然成功启动

但是，但是，创建admin用户密码的时候就报错了，ORA-01400: cannot insert NULL into (“DJANGO”.“AUTH_USER”.“ID”)

PS D:\parttime\python\django\guanxiangzhiji> python manage.py createsuperuser用户名 (leave blank to use 'administrator'):电子邮件地址:Password:Password (again):密码长度太短。密码必须包含至少 8 个字符。这个密码太常见了。Bypass password validation and create user anyway? [y/N]: yTraceback (most recent call last): File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute return self.cursor.execute(sql, params) File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute return self.cursor.execute(query, self._param_generator(params))cx_Oracle.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")The above exception was the direct cause of the following exception:Traceback (most recent call last): File "manage.py", line 21, in <module> main() File "manage.py", line 17, in main execute_from_command_line(sys.argv) File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 381, in execute_from_command_line utility.execute() File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 375, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 323, in run_from_argv self.execute(*args, **cmd_options) File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 61, in execute return super().execute(*args, **options) File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 364, in execute output = self.handle(*args, **options) File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 156, in handle self.UserModel._default_manager.db_manager(database).create_superuser(**user_data) File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 162, in create_superuser return self._create_user(username, email, password, **extra_fields) File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 145, in _create_user user.save(using=self._db) File "D:\app\anaconda\lib\site-packages\django\contrib\auth\base_user.py", line 66, in save super().save(*args, **kwargs) File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 741, in save force_update=force_update, update_fields=update_fields) File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 779, in save_base force_update, using, update_fields, File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 870, in _save_table result = self._do_insert(cls._base_manager, using, fields, update_pk, raw) File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 908, in _do_insert using=using, raw=raw) File "D:\app\anaconda\lib\site-packages\django\db\models\manager.py", line 82, in manager_method return getattr(self.get_queryset(), name)(*args, **kwargs) File "D:\app\anaconda\lib\site-packages\django\db\models\query.py", line 1186, in _insert return query.get_compiler(using=using).execute_sql(return_id) File "D:\app\anaconda\lib\site-packages\django\db\models\sql\compiler.py", line 1335, in execute_sql cursor.execute(sql, params) File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 99, in execute return super().execute(sql, params) File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 67, in execute return self._execute_with_wrappers(sql, params, many=False, executor=self._execute) File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 76, in _execute_with_wrappers return executor(sql, params, many, context) File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute return self.cursor.execute(sql, params) File "D:\app\anaconda\lib\site-packages\django\db\utils.py", line 89, in __exit__ raise dj_exc_value.with_traceback(traceback) from exc_value File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute return self.cursor.execute(sql, params) File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute return self.cursor.execute(query, self._param_generator(params))django.db.utils.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")

原因分析

很明显，插入到AUTH_USER表时，没有指定ID的值，而ID是主键，非空。

因为在12c的环境下，这个ID是自增序列，insert语句中不需要指定这个值。

解决方案

解决方案也应运而出了，只要为每个ID列创建一个11g的序列，创建触发器，在插入数据时补上id值就行了。

（1）生成序列。

用sql语句

select 'create sequence seq_'||table_name||' minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;' from user_tab_columns where column_name='ID';

生成创建序列的批量执行语句，并执行。

create sequence seq_DJANGO_ADMIN_LOG minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_USER minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_USER_GROUPS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_DJANGO_CONTENT_TYPE minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_GROUP minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_GROUP_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_DJANGO_MIGRATIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_PERMISSION minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;create sequence seq_AUTH_USER_USER_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;

（2）创建触发器

用SQL语句

select 'create or replace trigger tri_'||table_name||' before insert on '||table_name||' for each row declare begin :new.id:=seq_'||table_name||'.nextval; end tri_'||table_name||'; /' from user_tab_columns where column_name='ID';

生成触发器脚本：

create or replace trigger tri_DJANGO_MIGRATIONSbefore inserton DJANGO_MIGRATIONSfor each rowdeclarebegin:new.id:=seq_DJANGO_MIGRATIONS.nextval;end tri_DJANGO_MIGRATIONS;/create or replace trigger tri_DJANGO_CONTENT_TYPEbefore inserton DJANGO_CONTENT_TYPEfor each rowdeclarebegin:new.id:=seq_DJANGO_CONTENT_TYPE.nextval;end tri_DJANGO_CONTENT_TYPE;/create or replace trigger tri_AUTH_PERMISSIONbefore inserton AUTH_PERMISSIONfor each rowdeclarebegin:new.id:=seq_AUTH_PERMISSION.nextval;end tri_AUTH_PERMISSION;/create or replace trigger tri_AUTH_GROUPbefore inserton AUTH_GROUPfor each rowdeclarebegin:new.id:=seq_AUTH_GROUP.nextval;end tri_AUTH_GROUP;/create or replace trigger tri_AUTH_GROUP_PERMISSIONSbefore inserton AUTH_GROUP_PERMISSIONSfor each rowdeclarebegin:new.id:=seq_AUTH_GROUP_PERMISSIONS.nextval;end tri_AUTH_GROUP_PERMISSIONS;/create or replace trigger tri_AUTH_USERbefore inserton AUTH_USERfor each rowdeclarebegin:new.id:=seq_AUTH_USER.nextval;end tri_AUTH_USER;/create or replace trigger tri_AUTH_USER_GROUPSbefore inserton AUTH_USER_GROUPSfor each rowdeclarebegin:new.id:=seq_AUTH_USER_GROUPS.nextval;end tri_AUTH_USER_GROUPS;/create or replace trigger tri_AUTH_USER_USER_PERMISSIONSbefore inserton AUTH_USER_USER_PERMISSIONSfor each rowdeclarebegin:new.id:=seq_AUTH_USER_USER_PERMISSIONS.nextval;end tri_AUTH_USER_USER_PERMISSIONS;/create or replace trigger tri_DJANGO_ADMIN_LOGbefore inserton DJANGO_ADMIN_LOGfor each rowdeclarebegin:new.id:=seq_DJANGO_ADMIN_LOG.nextval;end tri_DJANGO_ADMIN_LOG;/

（3）此时再创建admin用户，就成功了

新增用户lurenjia成功！

看完了这篇文章，相信你对django2.2连oracle11g版本冲突怎么办有了一定的了解，想了解更多相关知识，欢迎关注亿速云行业资讯频道，感谢各位的阅读！