参考原文：https://www.the5fire.com/python-remove-duplicates-in-list.html

需求：去list进行去重，去重后保证顺序不变

方法1：for循环

ids = [1, 2, 3, 3, 4, 2, 3, 4, 5, 6, 1]new_ids = []for id in ids: if id not in new_ids: new_ids.append(id)print("new_ids==>", new_ids)方法2：set

ids = [1,4,3,3,4,2,3,4,5,6,1]new_ids = list(set(ids))print(new_ids)

测试发现去重后不能保证原来的顺序

方法3：按照索引再次排序

ids = [1, 4, 3, 3, 4, 2, 3, 4, 5, 6, 1]new_ids = list(set(ids))new_ids.sort(key=ids.index)print(new_ids)方法4：用reduce

ids = [1,4,3,3,4,2,3,4,5,6,1]func = lambda x,y:x if y in x else x + [y]reduce(func, [[], ] + ids)[1, 4, 3, 2, 5, 6]

其中的 lambda x,y:x if y in x else x + [y] 等价于 lambda x,y: y in x and x or x+[y] 。
思路其实就是先把ids变为[[], 1,4,3,......] ,然后在利用reduce的特性

reduce()函数介绍