怎么在python中实现星星排列
这期内容当中小编将会给大家带来有关怎么在python中实现星星排列,文章内容丰富且以专业的角度为大家分析和叙述,阅读完这篇文章希望大家可以有所收获。
星星阵型1
def stars1(n):for i in range(1,n+1):str = "*"*iprint strif __name__ == "__main__":stars1(5)
星星阵型2
def stars2(n):for i in range(1,n+1):str = '*'*(n+1-i)print strif __name__ == "__main__":stars2(5)
星星阵型3
def stars3(n):for i in range(1,n+1):str = ' ' * (n-i) + '*' * iprint strif __name__ == "__main__":stars3(5)
星星阵型4
def stars4(n):for i in range(1,1+n):#total n line(s)str = ' '*(i-1) + '*'*(n+1-i)print strif __name__ == "__main__":stars4(5)
5. 菱形阵型
def stars5(n): RANGE1 = [2*i+1 for i in range(n)] RANGE2 = [2*i+1 for i in range(n)[::-1]][1:] RANGE = RANGE1 + RANGE2 RANGE_1 = [i for i in range(n)[::-1]] RANGE_2 = [i for i in range(n)[1:]] RANGE_12 = RANGE_1 + RANGE_2 for i in range(len(RANGE)): print ' '*RANGE_12[i] + '*'*RANGE[i] if __name__ == "__main__":stars5(5)
6. 沙漏阵型
def star6(n): a = [i*2+1 for i in range(n)[::-1]] b = [i*2+1 for i in range(n)][1:] aa = a + b d = [i for i in range(n)] e = [i for i in range(n)[::-1]][1:] dd = d + e for j in range(len(dd)): print ' '*dd[j] + '*'*aa[j] if __name__ == "__main__": star6(5)
上述就是小编为大家分享的怎么在python中实现星星排列了,如果刚好有类似的疑惑,不妨参照上述分析进行理解。如果想知道更多相关知识,欢迎关注亿速云行业资讯频道。
声明:本站所有文章资源内容,如无特殊说明或标注,均为采集网络资源。如若本站内容侵犯了原著者的合法权益,可联系本站删除。