javascript中遍历数组有哪几种方法？相信很多没有经验的人对此束手无策，为此本文总结了问题出现的原因和解决方法，通过这篇文章希望你能解决这个问题。


有几种方法可以遍历数组，下面将逐个罗列！

while循环

let index = 0;const array = [1, 2, 3, 4, 5];while (index < array.length) { console.log(array[index]); index++;}

for循环

const array = [1,2,3,4,5];for(let index=0;index<array.length;index++){ console.log(array[index]);}for(let index in array){ console.log(array[index]);}

forEach

const array=[1,2,3,4,5];array.forEach(function(current_value,index,array){ console.log(`At index ${index} in array ${array} the value is ${current_value}`)})

map

最后一个构造很有用，但是不会返回新数组，这对于你的特定情况可能是不希望的。map通过对每个元素应用一个函数然后返回新数组来解决此问题。

const array = [1,2,3,4,5];const square = x =>Math.pow(x,2);const squares = array.map(square);console.log(`${array}`);console.log(`${squares}`)

reduce

reduce()方法对累加器和数组中的每个元素(从左到右)应用一个函数，以将其减小为单个值

const array = [1,2,3,4,5];const sum = (x,y) => x + y;const array_sum = array.reduce(sum,0);console.log(`the sum of arrray:${array} is ${array_sum}`);

filter

根据布尔函数过滤筛选数组中的元素

const array = [1,2,3,4,5];const even = x => x%2 === 0;const even_array = array.filter(even);console.log(`even numbers in array ${array} : ${even_array}`);

every

得到了一个数组，想测试每个元素是否满足给定条件

const array = [1,2,3,4,5,8];const under_six = x => x<6;if(array.every(under_six)){ console.log(`every elemnet in the array is less than 6`);}else{ console.log(`at least one element in the array was bigger than 6`);}

some

测试是否至少有一个元素与布尔函数匹配

const array = [2,4,5,6,8];const over_five = x => x>5;if(array.some(over_five)){ console.log(`at least one element bigger than 5 was found`);}else{ console.log(`no element bigger than 5 was found`);}

到此就结束啦，如果还有其他的欢迎补充！

看完上述内容，你们掌握javascript中遍历数组有哪几种方法的方法了吗？如果还想学到更多技能或想了解更多相关内容，欢迎关注亿速云行业资讯频道，感谢各位的阅读！